12x^2+10x=28

Solution for 12x^2+10x=28 equation:

12x^2+10x=28

We move all terms to the left:

12x^2+10x-(28)=0

a = 12; b = 10; c = -28;
Δ = b2-4ac
Δ = 102-4·12·(-28)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-38}{2*12}=\frac{-48}{24}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+38}{2*12}=\frac{28}{24}
=1+1/6
$